Алгебра, вопрос задал юлия55сергеевна , 1 год назад

Найти значение синуса и  косинуса бетта, если

1)<var>\beta = 3 \pi</var><var>2) \beta = 4 \pi 3)\beta = 3,5 \pi 4)\beta = 5/2 \pi </var>

Ответы на вопрос

Ответил Voxman
2

 

<var>1) \ sin(3\pi) = sin(\pi + 2\pi) = sin(\pi) = 0\\\\ cos(3\pi) = cos(\pi + 2\pi) = cos(\pi) = -1\\\\ 2) \ sin(4\pi) = sin(2\pi + 2\pi) = sin(2\pi) = sin(0+2\pi) = sin(0) = 0\\\\ cos(4\pi) = cos(2\pi + 2\pi) = cos(2\pi) = cos(0+2\pi) = cos(0) = 1\\\\ </var>

 

 

<var>3) \ sin(3.5\pi) = sin(1.5\pi + 2\pi) = sin(1.5\pi) =\\ sin(\frac{\pi}{2}+\pi) = -sin(\frac{\pi}{2}) = -1\\\\ cos(3.5\pi) = cos(1.5\pi + 2\pi) = cos(1.5\pi) =\\ cos(\frac{\pi}{2}+\pi) = -cos(\frac{\pi}{2}) = 0\\\\ 4) \ sin(2.5\pi) = sin(\frac{\pi}{2}+2\pi) = sin(\frac{\pi}{2}) = 1\\\\ cos(2.5\pi) = cos(\frac{\pi}{2}+2\pi) = cos(\frac{\pi}{2}) = 0 </var>

 

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