Пожалуйста, распишите полное решение данных тригонометрических выражений.
Ответы на вопрос
1) sin(a-b)+cos a*sin b =sina*cosb - cosa*sin b+cos a*sin b=sin a*cos b
2) cos(пи/2 - t)*ctg(-t)/sin (пи/2+t) = - sin t *ctg t/cos t =(-sint*cost/sint)/cost =
= -cost/cost = -1
3) ctg(-t)*sin t +cos(пи + t)=-cost/sint*sin t -cost =-cost-cost=-2cost
<br /><br /><img src=[/tex] frac{cos(frac{pi}{2}-t)*ctg(-t)}{sin(frac{pi}{2}+t)}=frac{sint*ctg(-t)}{cost}=tgt*-(ctgt)=-1;" title="1) sin(alpha-beta)+cosalpha sinbeta=sinalpha cosbeta-sinbeta cosalpha+cosalpha sinbeta
=sinalpha cosbeta;" title="2) frac{cos(frac{pi}{2}-t)*ctg(-t)}{sin(frac{pi}{2}+t)}=frac{sint*ctg(-t)}{cost}=tgt*-(ctgt)=-1;" title="1) sin(alpha-beta)+cosalpha sinbeta=sinalpha cosbeta-sinbeta cosalpha+cosalpha sinbeta
=sinalpha cosbeta;" alt="2) frac{cos(frac{pi}{2}-t)*ctg(-t)}{sin(frac{pi}{2}+t)}=frac{sint*ctg(-t)}{cost}=tgt*-(ctgt)=-1;" title="1) sin(alpha-beta)+cosalpha sinbeta=sinalpha cosbeta-sinbeta cosalpha+cosalpha sinbeta
=sinalpha cosbeta;" />
[tex]3) ctg(-t)*sint+cos(pi+t)=-frac{cost}{sint}*sint-cost
=-cost-cost=-2cost." title="2) frac{cos(frac{pi}{2}-t)*ctg(-t)}{sin(frac{pi}{2}+t)}=frac{sint*ctg(-t)}{cost}=tgt*-(ctgt)=-1;" />
[tex]3) ctg(-t)*sint+cos(pi+t)=-frac{cost}{sint}*sint-cost
=-cost-cost=-2cost." alt="2) frac{cos(frac{pi}{2}-t)*ctg(-t)}{sin(frac{pi}{2}+t)}=frac{sint*ctg(-t)}{cost}=tgt*-(ctgt)=-1;" />
[tex]3) ctg(-t)*sint+cos(pi+t)=-frac{cost}{sint}*sint-cost
=-cost-cost=-2cost." />