Решите пожалуйста 119 пример, буду благодарен за помощь!!!
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Ответил m11m
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119.
![2 sqrt[6]{4 sqrt{2} }=2 sqrt[6]{2^2 sqrt{2} }=2*( sqrt{2^4*2} )^{ frac{1}{6} }=2*( sqrt{2^5} )^{ frac{1}{6} }= \
=2*(2^{ frac{5}{2} })^{ frac{1}{6} }=2*2^{ frac{5}{12} }=2^{ frac{12}{12}+ frac{5}{12} }=2^{ frac{17}{12} }](https://tex.z-dn.net/?f=2+sqrt%5B6%5D%7B4+sqrt%7B2%7D+%7D%3D2+sqrt%5B6%5D%7B2%5E2+sqrt%7B2%7D+%7D%3D2%2A%28+sqrt%7B2%5E4%2A2%7D+%29%5E%7B+frac%7B1%7D%7B6%7D+%7D%3D2%2A%28+sqrt%7B2%5E5%7D+%29%5E%7B+frac%7B1%7D%7B6%7D+%7D%3D+%5C+%0A%3D2%2A%282%5E%7B+frac%7B5%7D%7B2%7D+%7D%29%5E%7B+frac%7B1%7D%7B6%7D+%7D%3D2%2A2%5E%7B+frac%7B5%7D%7B12%7D+%7D%3D2%5E%7B+frac%7B12%7D%7B12%7D%2B+frac%7B5%7D%7B12%7D++%7D%3D2%5E%7B+frac%7B17%7D%7B12%7D+%7D++ "2 sqrt[6]{4 sqrt{2} }=2 sqrt[6]{2^2 sqrt{2} }=2*( sqrt{2^4*2} )^{ frac{1}{6} }=2*( sqrt{2^5} )^{ frac{1}{6} }= \
=2*(2^{ frac{5}{2} })^{ frac{1}{6} }=2*2^{ frac{5}{12} }=2^{ frac{12}{12}+ frac{5}{12} }=2^{ frac{17}{12} }")
![sqrt[4]{8 sqrt[3]{4} }=(2^3 sqrt[3]{2^2} )^{ frac{1}{4} }=(2^3*2^{ frac{2}{3} })^{ frac{1}{4} }=(2^{ frac{11}{3} })^{ frac{1}{4} }=2^{ frac{11}{12} }](https://tex.z-dn.net/?f=+sqrt%5B4%5D%7B8+sqrt%5B3%5D%7B4%7D+%7D%3D%282%5E3+sqrt%5B3%5D%7B2%5E2%7D+%29%5E%7B+frac%7B1%7D%7B4%7D+%7D%3D%282%5E3%2A2%5E%7B+frac%7B2%7D%7B3%7D+%7D%29%5E%7B+frac%7B1%7D%7B4%7D+%7D%3D%282%5E%7B+frac%7B11%7D%7B3%7D+%7D%29%5E%7B+frac%7B1%7D%7B4%7D+%7D%3D2%5E%7B+frac%7B11%7D%7B12%7D+%7D+ "sqrt[4]{8 sqrt[3]{4} }=(2^3 sqrt[3]{2^2} )^{ frac{1}{4} }=(2^3*2^{ frac{2}{3} })^{ frac{1}{4} }=(2^{ frac{11}{3} })^{ frac{1}{4} }=2^{ frac{11}{12} }")
Ответ: D)
Ответ: D)
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