РЕБЯЯЯТ РЕШИТЕ ПЛЗ ОЧЕНЬ СРОЧНО
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Ответил m11m
0
1.
![0.2*25^x+4*5^{x-1}=1 \
0.2*5^{2x}+4* frac{5^x}{5}-1=0 \ \
0.2*5^{2x}+0.8*5^x-1=0 \ \
y=5^x \ \
0.2y^2+0.8y-1=0 \
y^2+4y-5=0 \
D=16+20=36 \
y_{1}= frac{-4-6}{2}=-5 \ \
y_{2}= frac{-4+6}{2}=1](https://tex.z-dn.net/?f=0.2%2A25%5Ex%2B4%2A5%5E%7Bx-1%7D%3D1+%5C+%0A0.2%2A5%5E%7B2x%7D%2B4%2A+frac%7B5%5Ex%7D%7B5%7D-1%3D0+%5C++%5C+%0A0.2%2A5%5E%7B2x%7D%2B0.8%2A5%5Ex-1%3D0+%5C++%5C+%0Ay%3D5%5Ex+%5C++%5C+%0A0.2y%5E2%2B0.8y-1%3D0+%5C+%0Ay%5E2%2B4y-5%3D0+%5C+%0AD%3D16%2B20%3D36+%5C+%0Ay_%7B1%7D%3D+frac%7B-4-6%7D%7B2%7D%3D-5+%5C++%5C+%0Ay_%7B2%7D%3D+frac%7B-4%2B6%7D%7B2%7D%3D1+++ "0.2*25^x+4*5^{x-1}=1 \
0.2*5^{2x}+4* frac{5^x}{5}-1=0 \ \
0.2*5^{2x}+0.8*5^x-1=0 \ \
y=5^x \ \
0.2y^2+0.8y-1=0 \
y^2+4y-5=0 \
D=16+20=36 \
y_{1}= frac{-4-6}{2}=-5 \ \
y_{2}= frac{-4+6}{2}=1")
При у=-5
нет решений
При у=1
![5^x=1 \
x=0](https://tex.z-dn.net/?f=5%5Ex%3D1+%5C+%0Ax%3D0 "5^x=1 \
x=0")
Ответ: 0.
2.
![( sqrt[3]{3} )^x+( sqrt[3]{3} )^{x-3}=21 \ \
( sqrt[3]{3} )^x(1+( sqrt[3]{3} )^{-3})=21 \ \
3^{ frac{x}{3} }(1+3^{-1})=21 \ \
3^{ frac{x}{3} }(1+ frac{1}{3} )=21 \ \
3^{ frac{x}{3} }* frac{4}{3} =21 \ \
3^{ frac{x}{3} }=21* frac{3}{4} \ \
3^{ frac{x}{3} }= frac{3*7*3}{4} \ \
3^{ frac{x}{3} }= 3^2* frac{7}{4} \ \
(3^{ frac{x}{3} })^3=(3^2* frac{7}{4} )^3 \ \
3^x=3^6*( frac{7}{4} )^3](https://tex.z-dn.net/?f=%28+sqrt%5B3%5D%7B3%7D+%29%5Ex%2B%28+sqrt%5B3%5D%7B3%7D+%29%5E%7Bx-3%7D%3D21+%5C++%5C+%0A%28+sqrt%5B3%5D%7B3%7D+%29%5Ex%281%2B%28+sqrt%5B3%5D%7B3%7D+%29%5E%7B-3%7D%29%3D21+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%281%2B3%5E%7B-1%7D%29%3D21+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%281%2B+frac%7B1%7D%7B3%7D+%29%3D21+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%2A+frac%7B4%7D%7B3%7D+%3D21+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%3D21%2A+frac%7B3%7D%7B4%7D+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%3D+frac%7B3%2A7%2A3%7D%7B4%7D+%5C++%5C+%0A3%5E%7B+frac%7Bx%7D%7B3%7D+%7D%3D+3%5E2%2A+frac%7B7%7D%7B4%7D+%5C++%5C+%0A%283%5E%7B+frac%7Bx%7D%7B3%7D+%7D%29%5E3%3D%283%5E2%2A+frac%7B7%7D%7B4%7D+%29%5E3+%5C++%5C+%0A3%5Ex%3D3%5E6%2A%28+frac%7B7%7D%7B4%7D+%29%5E3++++ "( sqrt[3]{3} )^x+( sqrt[3]{3} )^{x-3}=21 \ \
( sqrt[3]{3} )^x(1+( sqrt[3]{3} )^{-3})=21 \ \
3^{ frac{x}{3} }(1+3^{-1})=21 \ \
3^{ frac{x}{3} }(1+ frac{1}{3} )=21 \ \
3^{ frac{x}{3} }* frac{4}{3} =21 \ \
3^{ frac{x}{3} }=21* frac{3}{4} \ \
3^{ frac{x}{3} }= frac{3*7*3}{4} \ \
3^{ frac{x}{3} }= 3^2* frac{7}{4} \ \
(3^{ frac{x}{3} })^3=(3^2* frac{7}{4} )^3 \ \
3^x=3^6*( frac{7}{4} )^3")
![x=log_{3}(3^6*( frac{7}{4} )^3) \ \
x=log_{3}3^6+log_{3}( frac{7}{4} )^3 \ \
x=6+3log_{3}( frac{7}{4} ) \ \
x=6+3log_{3}7-3log_{3}4](https://tex.z-dn.net/?f=x%3Dlog_%7B3%7D%283%5E6%2A%28+frac%7B7%7D%7B4%7D+%29%5E3%29+%5C++%5C+%0Ax%3Dlog_%7B3%7D3%5E6%2Blog_%7B3%7D%28+frac%7B7%7D%7B4%7D+%29%5E3+%5C++%5C+%0Ax%3D6%2B3log_%7B3%7D%28+frac%7B7%7D%7B4%7D+%29+%5C++%5C+%0Ax%3D6%2B3log_%7B3%7D7-3log_%7B3%7D4 "x=log_{3}(3^6*( frac{7}{4} )^3) \ \
x=log_{3}3^6+log_{3}( frac{7}{4} )^3 \ \
x=6+3log_{3}( frac{7}{4} ) \ \
x=6+3log_{3}7-3log_{3}4")
Ответ:
При у=-5
нет решений
При у=1
Ответ: 0.
2.
Ответ:
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