Пожалуйста, решите уравнение.

2(1/2сosx-√3sinx)=2cos5x
2cos(x+π/3)=2cos5x
cos5x-cos(x+π/3)=0
-2sin(3x+π/6)sin(2x-π/6)=0
sin(3x+π/6)=0⇒3x+π/6=πn⇒3x=-π/6+πn⇒x=-π/18+πn/3
sin(2x-π/6)=0⇒2x-π/6=πn⇒2x=π/6+πn⇒x=π/12+πn/2