Математика, вопрос задал nikitaporfirew , 7 лет назад

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Математика​

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Ответил sonyamagonova
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frac{5}{6} - frac{3}{22} = frac{55}{66} - frac{9}{66} = frac{55 - 9}{66} = frac{46}{66} = frac{23}{33}0,75 - (frac{3}{16} + frac{1}{24}) = frac{3}{4}  - (frac{9}{48} + frac{2}{48}) = frac{3}{4} - frac{11}{48}  = frac{36}{48} - frac{11}{48} = frac{25}{48}

frac{9}{16} + (0,25 - frac{5}{24}) = frac{9}{16} + frac{1}{4}  - frac{5}{24} = frac{27}{48} + frac{12}{48} - frac{10}{48} = frac{29}{48}\\ 0,88 - frac{2}{15} = frac{22}{25} - frac{2}{15} = frac{66}{75} - frac{10}{75}  = frac{56}{75} \\(frac{1}{6} + frac{5}{18}) - (frac{1}{18} + frac{1}{24}) = (frac{3}{18} +  frac{5}{18}) - ( frac{1}{18} + frac{1}{24}) = frac{8}{18}  - (frac{4}{72} + frac{3}{72}) = frac{8}{18} - frac{7}{72} = frac{32}{72} - frac{7}{72} =

frac{25}{72} \4 - 2frac{4}{7} = 3frac{7}{7} - 2frac{4}{7} = 1frac{3}{7} \\2,5 + 1frac{2}{3} - 3frac{1}{6} = 2frac{1}{2} + 1frac{2}{3} - 3frac{1}{6} = 2frac{3}{6} + 1frac{4}{6} - 3frac{1}{6} = 1\\0,36 - frac{9}{75}  + frac{2}{15} = frac{9}{25} - frac{9}{75}  + frac{2}{15} =  frac{27}{75} - frac{9}{75}  + frac{10}{75} = frac{28}{75} \\( frac{1}{2} - frac{1}{3}) - (frac{1}{4} - frac{1}{5}) = (frac{3}{6} - frac{2}{6}) - (frac{5}{20} - frac{4}{20})=frac{1}{6} -frac{1}{20}= frac{10}{60} - frac{3}{60} = frac{7}{60}   \\3frac{2}{9} + 4frac{1}{6} - 1frac{8}{27}  = 3frac{12}{54} + 4frac{9}{54} - 1frac{16}{54} =  6frac{5}{54} \\11 - 6frac{2}{3} -3 frac{5}{7} = 10frac{21}{21} - 6frac{14}{21} - 3 frac{15}{21} = 9frac{42}{21} - 6frac{14}{21} - 3 frac{15}{21} = frac{13}{21} \\5frac{7}{12} - 2frac{4}{9} + 1frac{5}{18} =  5frac{21}{36} - 2frac{16}{36} + 1frac{10}{36} = 4frac{15}{36} =  4frac{5}{12}

frac{27}{75} + 0,32 - frac{7}{15} = frac{27}{75}  + frac{8}{25}  - frac{35}{75} = frac{27}{75}  + frac{24}{75}  - frac{35}{75} = frac{16}{75}\ \(frac{1}{3} - frac{1}{4}) - (frac{1}{5} - frac{1}{6}) = (frac{4}{12} - frac{3}{12}) - (frac{6}{30} -frac{5}{30}) = frac{1}{12} - frac{1}{30} = frac{5}{60} - frac{2}{60} = frac{3}{60} = frac{1}{2}

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