Плис срочно надо сделать

Объяснение:

sin(x/4+π/3)≤√2/2

0:

sin(x/4+π/3)=√2/2

x/4+π/3=π/4+2πk

x/4+π/3=3π/4+2πk

x/4=-π\12+2πk

x/4=5π/12+2πk

x=-π/3+8π(k+1)

x=5π/3+8πk

5π/3+8πk≤x≤-π/3+8π(k+1)

tg²x-tgx≥0

tgx(tgx-1)≥0

tgx=0

x=πk

tgx≥1

π/4+πk≤x<π/2+πk

x=πk

π/4+πk≤x<π/2+πk