Найдите корни уравнения sinФи=-1 принадлежащие промежутку Фи[0;4pi]
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sin Фи = -1
Фи = -π/2 +2πn, n∈Z
Фи∈[0; 4π]
0≤ -π/2+2πn ≤ 4π
π/2 ≤ 2πn ≤ 4π +π/2
π/2 ≤ 2πn ≤ 9π/2
π ≤ n ≤ 9π
2*2π 2*2π
1/4 ≤ n ≤ 9/4
0.25 ≤ n ≤ 2.25
n=1 Фи= -π/2 +2π = 3π/2
n=2 Фи= -π/2 +2π*2 = -π/2 +4π = 7π/2
Ответ: 3π/2; 7π/2.
Фи = -π/2 +2πn, n∈Z
Фи∈[0; 4π]
0≤ -π/2+2πn ≤ 4π
π/2 ≤ 2πn ≤ 4π +π/2
π/2 ≤ 2πn ≤ 9π/2
π ≤ n ≤ 9π
2*2π 2*2π
1/4 ≤ n ≤ 9/4
0.25 ≤ n ≤ 2.25
n=1 Фи= -π/2 +2π = 3π/2
n=2 Фи= -π/2 +2π*2 = -π/2 +4π = 7π/2
Ответ: 3π/2; 7π/2.
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