find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70.

Ответ:

9, 11, 13

Пошаговое объяснение:

x - first odd integer

(x+2) and (x+4) - next two consecutive odd integers

x + 2(x+2) + 3(x+4) = 70

6x +4 + 12 = 70

6x = 54

x = 9