√2x-2=x-4
как решить?
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Ответил krugly1981
0
√2x - 2 = x - 4
2x - 2 = ( x - 4)²
2x - 2 = (x -4)(x - 4)
2x - 2 = x² - 4x - 4x + 16
2x - 2 = x² - 8x + 16
2x - 2 - x² + 8x - 16 = 0
- x² + 10x - 18 =0
x² - 10x + 18 = 0
D = (-10)² - 4 × 1 × 18 = 100 - 72 = 28
x₁,₂ = 10⁺/⁻√28/ 2
2x - 2 = ( x - 4)²
2x - 2 = (x -4)(x - 4)
2x - 2 = x² - 4x - 4x + 16
2x - 2 = x² - 8x + 16
2x - 2 - x² + 8x - 16 = 0
- x² + 10x - 18 =0
x² - 10x + 18 = 0
D = (-10)² - 4 × 1 × 18 = 100 - 72 = 28
x₁,₂ = 10⁺/⁻√28/ 2
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