1) 81a³+18a²+a=0
2)a³-3a²-4a+12=0​

reginasatlykova574: 1. a^3-3a^2-4a+12=0a
3
−3a
2
−4a+12=0

a^2(a-3)-4(a-3)=(a-3)(a^2-4)=0a
2
(a−3)−4(a−3)=(a−3)(a
2
−4)=0

a-3=0a−3=0

a_1=3a
1
​
=3

a^2-4=0a
2
−4=0

(a-2)(a+2)=0(a−2)(a+2)=0

a_2=2a
2
​
=2

a_3=-2a
3
​
=−2

2.y^3+8+2(y+2)=0y
3
+8+2(y+2)=0

(y+2)(y^2-2y+4)+2(y+2)=(y+2)(y^2-2y+4+2)=(y+2)(y
2
−2y+4)+2(y+2)=(y+2)(y
2
−2y+4+2)=

=(y+2)(y^2-2y+6)=(y+2)(y
2
−2y+6)

y+2=0

y=-2

y^2-2y+6=0y
2
−2y+6=0

D<0 реш. нет

Ответ -2